C++..plz help with program codes using 'for' loop to get the foll: outputs:?

A


B B


C C C


D D D D


E E E E E





A


A B


A B C


A B C D


A B C D E





it would be nice if you could give me a bit of explanation too... :)

C++..plz help with program codes using 'for' loop to get the foll: outputs:?
//Hi... Here is the Code


//(1)


#include%26lt;iostream.h%26gt;


int main()


{


int r,d,c;


char a;


a='A';


d=a;


for(r=0;r%26lt;5;r++)


{


d=65+r;


a=d;


for(c=0;c%26lt;=r;c++)


{


cout%26lt;%26lt;a;


}


cout%26lt;%26lt;endl;


}


return 0;


}


//Here ASCII Code is used for printing the Characters.


//------------------------------------...


//Here is the Second one


//(2)


#include%26lt;iostream.h%26gt;


int main()


{


int r,c,d;


char a;


a='A';


d=a; //ASCII Code of 'A' is sent to int d.


for(r=1;r%26lt;=5;r++)


{


d=65; // ASCII code of A (65).


a=d;


for(c=1;c%26lt;=r;c++)


{


cout%26lt;%26lt;a;


d++; //increment in ASCII Code to print next character.


a=d;


}


cout%26lt;%26lt;endl;


}


return 0;


}


//Here ASCII Code is used for printing the Characters.
Reply:I cant give you the full code but but I can give you a hint. you have to use two for loops and ASCII values to print the patterns of Alphabets. ASCII value of A=65, B=66 .......... and so on





you can see my blog http://codesbyshariq.blogspot.com for more information
Reply:well even i struggle while doin these pattern problems....too bad i dont remember the code....but u will need one loop for the 5 rows....u can see tht the number of letters are equal to the number of row....i.e a is 1time and it is in 1st row...b is in 2nd row n it is 2 times....tht is the logic tht u hav to apply...


so u need a loop to change the row,one loop for printing the alphabets....this is the solution to the first pattern....similarly u can solve the second pattern...
Reply:int c=1;


for(int i=65;i%26lt;=65+27 /* this is the number of capital letters*/;i++)


{


for(int x=1;x%26lt;=c;x++)


{


printf("%c",i);


}


printf("\n");


c++;


}


//***** this would do the first series


//*** now the second one:


int c=1;


for(int i=65;i%26lt;=65+27 /* this is the number of capital letters*/;i++)


{


for(int x=0;x%26lt;=c;x++)


{


printf("%c",x+65);


}


printf("\n");


c++;


}


//******* END**********//





I did not have the chance to code it and probe it, but I think It works.